Which is the correct order for the solubility of the following compounds in $n$-octane (at identical conditions)? $I$) Cyclohexane $II$) $KCl$ $III$) $CH_3OH$ $IV$) $CH_3CN$

• A
  $II < III < IV < I$
• B
  $II < III < IV < I$ (Note: Corrected sequence based on polarity: $II < III < IV < I$)
• C
  $I < IV < III < II$
• D
  $I < III < IV < II$