Which is the incorrect order of increasing ac | vedclass

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(D) The acidic strength of carboxylic acids depends on the electron-withdrawing effect of substituents. Electron-withdrawing groups $(EWG)$ increase a

Vedclass · Accepted Answer

$HCOOH < C_6H_5COOH$

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(D) The acidic strength of carboxylic acids depends on the electron-withdrawing effect of substituents. Electron-withdrawing groups $(EWG)$ increase acidity by stabilizing the carboxylate anion,while electron-donating groups decrease it.$A$. $CH_2FCH_2CH_2COOH $B$. $CH_2ClCOOH $C$. $CH_3COOH $D$. $HCOOH < C_6H_5COOH$: Incorrect. Formic acid $(HCOOH)$ is more acidic than benzoic acid $(C_6H_5COOH)$ because the phenyl group in benzoic acid is electron-donating by resonance and has a weaker $-I$ effect compared to the hydrogen atom in formic acid. Thus,the correct order is $C_6H_5COOH < HCOOH$.

Which is the incorrect order of increasing acidic strength for the following?

Similar Questions

$CH_3 - CH = CH - CH_2 - CO_2H \xrightarrow[\Delta ]{}(X) \,(major)$; Product $(X)$ is

The major product $H$ in the given reaction sequence is:
$CH_3-CH_2-CO-CH_3$ $\xrightarrow{CN^-} G$ $\xrightarrow{95\% \ H_2SO_4, \Delta} H$

Identify the product of the following reaction:

For the following three esters, the order of rates of alkaline hydrolysis is:
$(I)$ $p-NO_2-C_6H_4-COOCH_3$
$(II)$ $p-CH_3O-C_6H_4-COOCH_3$
$(III)$ $p-CH_3-C_6H_4-COOCH_3$

Dimerization in carboxylic acids is due to which of the following?

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