(A) When methane $(CH_4)$ is treated with chlorine $(Cl_2)$ in the presence of $UV$ light,a free radical substitution reaction occurs.Since methane is

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(A) When methane $(CH_4)$ is treated with chlorine $(Cl_2)$ in the presence of $UV$ light,a free radical substitution reaction occurs.Since methane is taken in excess,the reaction is limited to the first step of substitution.The reaction is: $CH_4 + Cl_2 \xrightarrow{UV \ light} CH_3Cl + HCl$.Therefore,the major product formed is chloromethane $(CH_3Cl)$.

Class 11 Chemistry Hydrocarbons Alkane

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Which major product is formed when excess of methane is treated with chlorine in the presence of $UV$ light?

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A
Chloromethane
B
Dichloromethane
C
Trichloromethane
D
Tetrachloromethane

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Which major product is formed when excess of methane is treated with chlorine in the presence of $UV$ light?

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