Which molecule AX_3,AX_4,AX_5,AX_6 is most li | vedclass

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(B) According to the $VSEPR$ theory,the molecular geometry depends on the number of bonding pairs and lone pairs around the central atom $A$.For a mol

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$AX_5$

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(B) According to the $VSEPR$ theory,the molecular geometry depends on the number of bonding pairs and lone pairs around the central atom $A$.For a molecule with no lone pairs on the central atom:$1$. $AX_3$ has $3$ bonding pairs,resulting in a trigonal planar geometry.$2$. $AX_4$ has $4$ bonding pairs,resulting in a tetrahedral geometry.$3$. $AX_5$ has $5$ bonding pairs,resulting in a trigonal bipyramidal geometry.$4$. $AX_6$ has $6$ bonding pairs,resulting in an octahedral geometry.Therefore,the molecule $AX_5$ with no lone pair on $A$ has a trigonal bipyramidal structure.

Which molecule $AX_3$,$AX_4$,$AX_5$,$AX_6$ is most likely to have a trigonal bipyramidal structure if $A$ has no lone pair?

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