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Question

(C) In $NCl_3$ and $N(CH_3)_3$,the nitrogen atom is bonded to three atoms and has one lone pair,resulting in $sp^3$ hybridisation and a pyramidal geom

Vedclass · Accepted Answer

$N(SiH_3)_3$

Vedclass · Answer

(C) In $NCl_3$ and $N(CH_3)_3$,the nitrogen atom is bonded to three atoms and has one lone pair,resulting in $sp^3$ hybridisation and a pyramidal geometry.In $N(SiH_3)_3$,the lone pair on the nitrogen atom is donated into the vacant $d$-orbital of the silicon atom due to $p\pi-d\pi$ back-bonding.This back-bonding changes the geometry of the nitrogen atom from pyramidal to planar,making the nitrogen atom $sp^2$ hybridised.

Which molecule is $sp^2$ hybridised?

Similar Questions

The compounds with $sp^2$ hybridized central atom among the following are:
$(A)$ $H_2CO_3$
$(B)$ $SiF_4$
$(C)$ $BF_3$
$(D)$ $HClO_2$

Which of the following molecules has a shape similar to $CO_{2}$?

Which of the underlined atoms in the molecules shown below have $sp$-hybridization?
$(u) H_2\underline{C}=CH-CH_3$
$(v) CH_2=\underline{C}=CHCl$
$(w) CH_3-\underline{C}H_2^+$
$(x) H-C \equiv C-H$
$(y) CH_3-\underline{C} \equiv N$
$(z) (CH_3)_2C=\underline{N}-NH_2$

Suggest reasons why the $B-F$ bond lengths in $BF_3\ (130\ pm)$ and $BF_4^-\ (143\ pm)$ differ.

Explain bond formation in $BCl_{3}$. It is a symmetrical trigonal molecule.

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