Which of the following 0.10 m aqueous soluti | vedclass

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(A) The depression in freezing point $\Delta T_f$ is directly proportional to the van't Hoff factor $i$ for solutions of the same molality: $\Delta T_

Vedclass · Accepted Answer

$Al_2(SO_4)_3$

Vedclass · Answer

(A) The depression in freezing point $\Delta T_f$ is directly proportional to the van't Hoff factor $i$ for solutions of the same molality: $\Delta T_f = i 	imes K_f 	imes m$. Since the molality $m$ is the same for all,the solution with the highest value of $i$ will have the greatest depression in freezing point and thus the lowest freezing point. $1$. $Al_2(SO_4)_3 ightarrow 2Al^{3+} + 3SO_4^{2-}$ $(i = 5)$ $2$. $C_6H_{12}O_6$ (glucose) is a non-electrolyte $(i = 1)$ $3$. $KCl ightarrow K^{+} + Cl^{-}$ $(i = 2)$ $4$. $C_{12}H_{22}O_{11}$ (sucrose) is a non-electrolyte $(i = 1)$ Since $Al_2(SO_4)_3$ has the highest van't Hoff factor $(i = 5)$,it will show the maximum depression in freezing point,resulting in the lowest freezing point.

Which of the following $0.10 \ m$ aqueous solutions will have the lowest freezing point?

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