Which of the following amines forms a clear s | vedclass

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(D) The reaction with benzene sulphonyl chloride (Hinsberg's reagent) is used to distinguish between primary,secondary,and tertiary amines.Primary ami

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$CH_{3}NH_{2}$

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(D) The reaction with benzene sulphonyl chloride (Hinsberg's reagent) is used to distinguish between primary,secondary,and tertiary amines.Primary amines $(R-NH_{2})$ react with benzene sulphonyl chloride to form $N$-alkylbenzene sulphonamide,which contains an acidic hydrogen atom attached to the nitrogen.This acidic hydrogen makes the product soluble in excess of potassium hydroxide $(KOH)$,resulting in a clear solution.Secondary amines $(R_{2}NH)$ form $N,N$-dialkylbenzene sulphonamides,which lack an acidic hydrogen and are insoluble in $KOH$.Tertiary amines $(R_{3}N)$ do not react with benzene sulphonyl chloride.Among the given options,$CH_{3}NH_{2}$ is a primary amine,so it forms a clear solution.

$Test/Method$	$Reagent$
$(i)$ Lucas Test	$(a)$ $C_6H_5SO_2Cl/aq. KOH$
$(ii)$ Dumas method	$(b)$ $HNO_3/AgNO_3$
$(iii)$ Kjeldahl's method	$(c)$ $CuO/CO_2$
$(iv)$ Hinsberg Test	$(d)$ Conc. $HCl$ and $ZnCl_2$
	$(e)$ $H_2SO_4$

Which of the following amines forms a clear solution when treated with benzene sulphonyl chloride and excess of potassium hydroxide?

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Match the following:
$Test/Method$ $Reagent$
$(i)$ Lucas Test $(a)$ $C_6H_5SO_2Cl/aq. KOH$
$(ii)$ Dumas method $(b)$ $HNO_3/AgNO_3$
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$(e)$ $H_2SO_4$

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