Which of the following are diamagnetic?I. K_4 | vedclass

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(B) $I. K_4[Fe(CN)_6]$: $Fe^{2+}$ is $d^6$. $CN^-$ is a strong field ligand,so electrons pair up. $t_{2g}^6 e_g^0$. Diamagnetic.$II. K_3[Cr(CN)_6]$: $

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$I, III$ and $IV$

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(B) $I. K_4[Fe(CN)_6]$: $Fe^{2+}$ is $d^6$. $CN^-$ is a strong field ligand,so electrons pair up. $t_{2g}^6 e_g^0$. Diamagnetic.$II. K_3[Cr(CN)_6]$: $Cr^{3+}$ is $d^3$. $t_{2g}^3$. Paramagnetic due to $3$ unpaired electrons.$III. K_3[Co(CN)_6]$: $Co^{3+}$ is $d^6$. $CN^-$ is a strong field ligand,so electrons pair up. $t_{2g}^6 e_g^0$. Diamagnetic.$IV. K_2[Ni(CN)_4]$: $Ni^{2+}$ is $d^8$. $CN^-$ is a strong field ligand,leading to $dsp^2$ hybridization. All electrons are paired. Diamagnetic.Thus,$I, III$ and $IV$ are diamagnetic.

Which of the following are diamagnetic?
$I. K_4[Fe(CN)_6]$
$II. K_3[Cr(CN)_6]$
$III. K_3[Co(CN)_6]$
$IV. K_2[Ni(CN)_4]$
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Which of the following are diamagnetic?$I. K_4[Fe(CN)_6]$$II. K_3[Cr(CN)_6]$$III. K_3[Co(CN)_6]$$IV. K_2[Ni(CN)_4]$Select the correct answer using the codes given below: