Which of the following can show geometrical i | vedclass

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(C) Geometrical isomerism requires restricted rotation (like a double bond or a ring) and different groups attached to each carbon atom involved in th

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$1-$ethyl$-2-$methylcyclobutane

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(C) Geometrical isomerism requires restricted rotation (like a double bond or a ring) and different groups attached to each carbon atom involved in the restricted rotation.$A$: $2,3$-dimethylbut-$2$-ene is $(CH_3)_2C=C(CH_3)_2$. Both carbons of the double bond have identical methyl groups,so it cannot show geometrical isomerism.$B$: $1$-methylcyclohex-$1$-ene has the double bond within a six-membered ring. The carbons at positions $1$ and $2$ are part of the ring,and the geometry is fixed,preventing cis-trans isomerism in such a small ring.$C$: $1$-ethyl-$2$-methylcyclobutane has a cyclic structure. The substituents at positions $1$ and $2$ can be on the same side (cis) or opposite sides (trans) of the ring plane,thus it shows geometrical isomerism.$D$: $CH_3-C \equiv C-CH_2CH_3$ contains a triple bond,which is linear and cannot show geometrical isomerism.

Which of the following can show geometrical isomerism?

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