Which of the following can undergo Hell-Volha | vedclass

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(B) The Hell-Volhard-Zelinsky $(HVZ)$ reaction is a characteristic reaction of carboxylic acids that possess at least one $\alpha$-hydrogen atom. In t

Vedclass · Accepted Answer

$C_6H_5CH_2COOH$

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(B) The Hell-Volhard-Zelinsky $(HVZ)$ reaction is a characteristic reaction of carboxylic acids that possess at least one $\alpha$-hydrogen atom. In this reaction,the $\alpha$-hydrogen is replaced by a halogen atom (usually $Br_2$ or $Cl_2$) in the presence of a small amount of red phosphorus. Let us analyze the given options: $(A)$ $C_6H_5COOH$ (Benzoic acid): The carbon atom attached to the $-COOH$ group is part of the benzene ring and has no $\alpha$-hydrogen. $(B)$ $C_6H_5CH_2COOH$ (Phenylacetic acid): The carbon atom attached to the $-COOH$ group is a $CH_2$ group,which contains two $\alpha$-hydrogen atoms. Thus,it can undergo the $HVZ$ reaction. $(C)$ $C_6H_5CH_2CHO$ (Phenylacetaldehyde): This is an aldehyde,not a carboxylic acid. $(D)$ $C_6H_5CH_2COCH_3$ ($1$-Phenylpropan$-2-$one): This is a ketone,not a carboxylic acid. Therefore,only $C_6H_5CH_2COOH$ satisfies the condition for the $HVZ$ reaction.

Which of the following can undergo Hell-Volhard-Zelinsky reaction?

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