Which of the following carbocations will not | vedclass

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Question

(B) Rearrangement of carbocations occurs to form a more stable carbocation (e.g.,primary to secondary,or secondary to tertiary,or resonance-stabilized

Vedclass · Accepted Answer

$1-$Phenyl$-1-$propyl carbocation

Vedclass · Answer

(B) Rearrangement of carbocations occurs to form a more stable carbocation (e.g.,primary to secondary,or secondary to tertiary,or resonance-stabilized). $A$. The isobutyl carbocation $(CH_3)_2CH-CH_2^+$ is a primary carbocation that undergoes a $1,2$-hydride shift to form a more stable tertiary carbocation $(CH_3)_2C^+-CH_3$. $B$. The $1$-phenyl-$1$-propyl carbocation $(Ph-CH^+-CH_2-CH_3)$ is already resonance-stabilized by the phenyl ring and is a secondary carbocation. It does not undergo further rearrangement because it is already highly stable. $C$. The $2$-ethylcyclohexyl carbocation is a secondary carbocation that can undergo ring expansion or hydride shifts to form more stable carbocations. $D$. The $2-(1,2,3,4-tetrahydronaphthalen-2-yl)ethyl$ carbocation is a primary carbocation that can undergo rearrangement to form a more stable secondary or tertiary carbocation. Therefore,the $1$-phenyl-$1$-propyl carbocation is the most stable among the options and does not undergo rearrangement.

Which of the following carbocations will not undergo rearrangement?

Similar Questions

Consider the following carbocations:
$I. C_6H_5CH_2^+$
$II. CH_2=CH^+$
$III. CH_3-CH^+(CH_3)$
$IV. CH_3-CH_2^+$
$V. HC \equiv C^+$
Arrange the above carbocations in the order of decreasing stability.

Carbocation as an intermediate is likely to be formed in the reaction:

$CH_3-C(CH_3)_2-CH_2-CH_2^+ \to CH_3-C^+(CH_3)-CH(CH_3)-CH_3$
How many $H^-$ shifts are involved in the above rearrangement?

Which of the following carbocations will be most stable?

Which of the following is most stable?

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