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(A) To find the correct circuit,we analyze the output $C$ for each input combination $(A, B)$:$1$. For $(A=0, B=0)$,$C=0$.$2$. For $(A=0, B=1)$,$C=0$.

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(A) To find the correct circuit,we analyze the output $C$ for each input combination $(A, B)$:$1$. For $(A=0, B=0)$,$C=0$.$2$. For $(A=0, B=1)$,$C=0$.$3$. For $(A=1, B=0)$,$C=1$.$4$. For $(A=1, B=1)$,$C=0$.This truth table corresponds to the Boolean expression $C = A \cdot \overline{B}$.Now,let's analyze the circuit in option $A$ (image $823-a813$):- The input $A$ goes into an $AND$ gate and also through a $NOT$ gate.- The input $B$ goes into the $AND$ gate.- The output of the $AND$ gate is $A \cdot B$.- The output of the $NOT$ gate is $\overline{A}$.- These are fed into a $NOR$ gate,giving $C = \overline{(A \cdot B) + \overline{A}} = \overline{A \cdot B} \cdot A = (\overline{A} + \overline{B}) \cdot A = A \cdot \overline{B}$.This matches the required truth table. Thus,the circuit in option $A$ is correct.

Which of the following circuits correctly represents the following truth table?
$A$ $B$ $C$
$0$ $0$ $0$
$0$ $1$ $0$
$1$ $0$ $1$
$1$ $1$ $0$

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Which of the following circuits correctly represents the following truth table?$A$$B$$C$$0$$0$$0$$0$$1$$0$$1$$0$$1$$1$$1$$0$