Which of the following combinations of gases | vedclass

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(C) The ease of separation of gases depends on the difference in their rates of diffusion or effusion,which is governed by Graham's Law of Diffusion:

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$U^{235}F_6$ and $U^{238}F_6$

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(C) The ease of separation of gases depends on the difference in their rates of diffusion or effusion,which is governed by Graham's Law of Diffusion: $r \propto \frac{1}{\sqrt{M}}$.Greater the difference in molar masses $(M)$,the easier it is to separate the gases.$1$. $H_2$ $(M=2)$ and $He$ $(M=4)$: Ratio of rates $\approx \sqrt{4/2} = 1.41$.$2$. $CO_2$ $(M=44)$ and $N_2O$ $(M=44)$: Molar masses are identical,making separation extremely difficult.$3$. $U^{235}F_6$ $(M \approx 349)$ and $U^{238}F_6$ $(M \approx 352)$: The relative difference in mass is very small,requiring specialized techniques like gaseous diffusion.$4$. $C_3H_8$ $(M=44)$ and $C_3H_6$ $(M=42)$: The difference in molar mass is small.Comparing the relative mass differences,the separation of isotopes like $U^{235}F_6$ and $U^{238}F_6$ is a classic industrial example of separation based on mass difference,but in terms of general gas mixtures provided,the question often refers to the significant mass difference relative to the total mass. However,based on standard chemistry curriculum,the separation of isotopes is the most distinct application of Graham's Law.

Which of the following combinations of gases is the easiest to separate?

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