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(A) The magnitude of crystal field splitting energy $\Delta_0$ depends on: $1$. Oxidation state of the metal ion: Higher oxidation state leads to high

Vedclass · Accepted Answer

$I < II$

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(A) The magnitude of crystal field splitting energy $\Delta_0$ depends on: $1$. Oxidation state of the metal ion: Higher oxidation state leads to higher $\Delta_0$. $2$. Nature of the ligand: Strong field ligands (like $CN^-$) result in higher $\Delta_0$ than weak field ligands (like $H_2O$). $3$. Principal quantum number of the metal: $4d$ and $5d$ series have higher $\Delta_0$ than $3d$ series. Comparing the complexes: - For $I$ $(Co^{2+})$ and $II$ $(Co^{3+})$, both have $H_2O$ ligands. Since $Co^{3+}$ has a higher oxidation state, $\Delta_0(II) > \Delta_0(I)$. - For $II$ $(Co^{3+})$ and $III$ $(Fe^{3+})$, both have $H_2O$ ligands. $Co^{3+}$ has a higher effective nuclear charge than $Fe^{3+}$, so $\Delta_0(II) > \Delta_0(III)$. - For $II$ ($H_2O$ ligand) and $IV$ ($CN^-$ ligand), $CN^-$ is a much stronger field ligand than $H_2O$, so $\Delta_0(IV) > \Delta_0(II)$. Thus, the correct comparison is $I < II$.

Which of the following comparisons is correct for the crystal field splitting energy $\Delta_0$ of the following complexes?
$I$- $[Co(H_2O)_6]^{2+}$
$II$- $[Co(H_2O)_6]^{3+}$
$III$- $[Fe(H_2O)_6]^{3+}$
$IV$- $[Fe(CN)_6]^{3+}$

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Which of the following comparisons is correct for the crystal field splitting energy $\Delta_0$ of the following complexes? $I$- $[Co(H_2O)_6]^{2+}$ $II$- $[Co(H_2O)_6]^{3+}$ $III$- $[Fe(H_2O)_6]^{3+}$ $IV$- $[Fe(CN)_6]^{3+}$