Which of the following complexes is paramagne | vedclass

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(B) $1$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ $(3d^6)$,$CN^-$ is a strong field ligand. It forms $d^2sp^3$ (inner orbital) and is diamagnetic ($0$ unpaired el

Vedclass · Accepted Answer

$[Cr(NH_3)_6]^{3+}$

Vedclass · Answer

(B) $1$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ $(3d^6)$,$CN^-$ is a strong field ligand. It forms $d^2sp^3$ (inner orbital) and is diamagnetic ($0$ unpaired electrons).$2$. $[Cr(NH_3)_6]^{3+}$: $Cr^{3+}$ $(3d^3)$,$NH_3$ is a ligand. It forms $d^2sp^3$ (inner orbital) and is paramagnetic ($3$ unpaired electrons).$3$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ $(3d^6)$,$NH_3$ is a strong field ligand. It forms $d^2sp^3$ (inner orbital) and is diamagnetic ($0$ unpaired electrons).$4$. $[Fe(NO_2)_6]^{4-}$: $Fe^{2+}$ $(3d^6)$,$NO_2^-$ is a strong field ligand. It forms $d^2sp^3$ (inner orbital) and is diamagnetic ($0$ unpaired electrons).Thus,$[Cr(NH_3)_6]^{3+}$ is both paramagnetic and an inner orbital complex.

List-$I$ $(Compounds)$	List-$II$ $(Hybridization)$
$(a)$ $[Ni(NH_3)_6]^{+2}$	$(i)$ $sp^3 d^2$
$(b)$ $[PtCl_4]^{-2}$	$(ii)$ $dsp^2$
$(c)$ $[Ni(CO)_4]$	$(iii)$ $sp^3$
$(d)$ $[Co(OX)_3]^{-3}$	$(iv)$ $d^2 sp^3$

Which of the following complexes is paramagnetic and an inner orbital complex?

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