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(D) The $CFSE$ (Crystal Field Stabilization Energy) depends on the oxidation state of the metal,the nature of the ligand,and the $d$-electron configur

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$K_{3}[Co(CN)_{6}]$

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(D) The $CFSE$ (Crystal Field Stabilization Energy) depends on the oxidation state of the metal,the nature of the ligand,and the $d$-electron configuration.$1$. In $K_{3}[Fe(CN)_{6}]$,$Fe$ is in $+3$ oxidation state ($d^{5}$ configuration). $CN^{-}$ is a strong field ligand,resulting in a low-spin $t_{2g}^{5}e_{g}^{0}$ configuration. $CFSE = -2.0 \Delta_{o}$.$2$. In $K_{3}[Co(Ox)_{3}]$,$Co$ is in $+3$ oxidation state ($d^{6}$ configuration). $Ox^{2-}$ is a moderate field ligand,resulting in a low-spin $t_{2g}^{6}e_{g}^{0}$ configuration. $CFSE = -2.4 \Delta_{o}$.$3$. In $K_{3}[CoF_{6}]$,$Co$ is in $+3$ oxidation state ($d^{6}$ configuration). $F^{-}$ is a weak field ligand,resulting in a high-spin $t_{2g}^{4}e_{g}^{2}$ configuration. $CFSE = -0.4 \Delta_{o}$.$4$. In $K_{3}[Co(CN)_{6}]$,$Co$ is in $+3$ oxidation state ($d^{6}$ configuration). $CN^{-}$ is a strong field ligand,resulting in a low-spin $t_{2g}^{6}e_{g}^{0}$ configuration. $CFSE = -2.4 \Delta_{o}$.Comparing the magnitudes,$[Co(CN)_{6}]^{3-}$ and $[Co(Ox)_{3}]^{3-}$ have the highest $CFSE$ values. However,since $CN^{-}$ is a stronger field ligand than $Ox^{2-}$,$\Delta_{o}$ for $[Co(CN)_{6}]^{3-}$ is significantly larger,making its $CFSE$ the maximum.

Which of the following complexes has maximum $CFSE$?

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