Which of the following complexes has the maxi | vedclass

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(D) $1$. In $[Ni(CO)_4]$,$Ni$ is in $0$ oxidation state $(3d^8 4s^2)$. Since $CO$ is a strong field ligand,all electrons pair up,resulting in $0$ unpa

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$[CuBr_4]^{2-}$

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(D) $1$. In $[Ni(CO)_4]$,$Ni$ is in $0$ oxidation state $(3d^8 4s^2)$. Since $CO$ is a strong field ligand,all electrons pair up,resulting in $0$ unpaired electrons.$2$. In $[Co(NH_3)_4(NO_2)_2]^+$,$Co$ is in $+3$ oxidation state $(3d^6)$. $NH_3$ and $NO_2^-$ are strong field ligands,causing pairing of electrons,resulting in $0$ unpaired electrons.$3$. In $[Ag(CN)_2]^-$,$Ag^+$ has $d^{10}$ configuration,resulting in $0$ unpaired electrons.$4$. In $[CuBr_4]^{2-}$,$Cu$ is in $+2$ oxidation state $(3d^9)$. There is $1$ unpaired electron in the $d$-orbital.Comparing all,$[CuBr_4]^{2-}$ has the maximum number of unpaired electrons $(1)$.

Which of the following complexes has the maximum number of unpaired electrons?

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