Which of the following compounds has the smal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For series $(A)$,as the electronegativity of the halogen decreases,the electron density around the central atom increases,leading to greater repul

Vedclass · Accepted Answer

$OSF_2, SbCl_3$ and $SbI_3$

Vedclass · Answer

(D) For series $(A)$,as the electronegativity of the halogen decreases,the electron density around the central atom increases,leading to greater repulsion between the bonding pairs and the lone pair,which decreases the bond angle. Thus,$OSF_2$ has the smallest bond angle.For series $(B)$,as the electronegativity of the halogen decreases,the bond angle increases. Thus,$SbCl_3$ has the smallest bond angle.For series $(C)$,as we move down the group,the central atom size increases and the electronegativity decreases,leading to a decrease in the bond angle. Thus,$SbI_3$ has the smallest bond angle.Therefore,the correct sequence is $OSF_2, SbCl_3$ and $SbI_3$.

Similar Questions

The structures of $O_3$ and $N_3^-$ are

$A$ molecule $XY_2$ contains two $\sigma$,two $\pi$-bonds and one lone pair of electron in the valence shell of $X$. The arrangement of lone pair as bond pair is

Observe the following statements:
$i$. According to $\text{VSEPR}$ theory,$ClF_3$ and $SO_2$ are shown as $AB_3E_2$ and $AB_2E$ type molecules respectively.
$ii$. $SF_4$ has a "See-saw" shape.
$iii$. $HgCl_2$ and $PbCl_2$ have the same shape.
The statements which are not correct are:

$SF_4$ is isostructural with:

$A$ covalent molecule $AB_{3}$ has a pyramidal structure. The number of lone pairs and bond pairs of electrons in the molecule are respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module