Which of the following compounds will not be | vedclass

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(D) The reaction is a free radical bromination of $2$-bromopentane. The rate-determining step involves the abstraction of a hydrogen atom to form a fr

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(D) The reaction is a free radical bromination of $2$-bromopentane. The rate-determining step involves the abstraction of a hydrogen atom to form a free radical. The most stable free radical is formed at the $C-3$ position. Since the chiral center at $C-2$ is not involved in the reaction,its configuration remains unchanged. The $C-3$ carbon becomes a new chiral center upon bromination,leading to two diastereomers. The configuration at $C-2$ is fixed as $S$ in the starting material. Therefore,the products must retain the $S$ configuration at $C-2$. The option showing a change in configuration at $C-2$ (i.e.,$2R, 3S$) is not possible.

Which of the following compounds will not be obtained as a product in the above reaction?

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