Which of the following compounds will not sho | vedclass

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(A) For a compound to show geometrical isomerism,each carbon atom of the double bond must be attached to two different groups. In option $A$,the cyclo

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(A) For a compound to show geometrical isomerism,each carbon atom of the double bond must be attached to two different groups. In option $A$,the cyclopropylidene carbon is attached to two identical methyl groups $(-CH_3)$. Since the groups on one side of the double bond are identical,it cannot exhibit geometrical isomerism. Therefore,the correct option is $A$.

Which of the following compounds will not show geometrical isomerism across the $\pi$-bond?

Similar Questions

Which of the following compounds can show geometrical isomerism:
$I$. $CH_3-CH=CH-CH_2-CH_3$
$II$. $1,2$-dimethylcyclohexane
$III$. $CH_3-N=CH_2$
$IV$. $C_2H_5-CH=N-OH$

The alkene that exhibits geometrical isomerism is ...... .

The alkene that exhibits geometrical isomerism is:

What are the correct $E/Z$ designations for the structure below?

Which of the following compounds will exhibit $cis-trans$ (geometrical) isomerism?

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