Which of the following compounds shows optica | vedclass

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(C) Optical isomerism is shown by coordination compounds that lack a plane of symmetry and a center of symmetry.$A$. $[Cu(NH_3)_4]^{2+}$ is a square p

Vedclass · Accepted Answer

$[Cr(C_2O_4)_3]^{3-}$

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(C) Optical isomerism is shown by coordination compounds that lack a plane of symmetry and a center of symmetry.$A$. $[Cu(NH_3)_4]^{2+}$ is a square planar complex,which is achiral.$B$. $[ZnCl_4]^{2-}$ is a tetrahedral complex with identical ligands,which is achiral.$C$. $[Cr(C_2O_4)_3]^{3-}$ is an octahedral complex with three bidentate oxalate ligands. It exists as a pair of non-superimposable mirror images (enantiomers),thus showing optical isomerism.$D$. $[Co(CN)_6]^{3-}$ is an octahedral complex with identical ligands,which is achiral.Therefore,the correct option is $C$.

Which of the following compounds shows optical isomerism?

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