Which of the following compounds shows the hy | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the molecule $H_2C = CH - C \equiv N$:$1$. The first carbon atom $(CH_2)$ is bonded to two hydrogens and one double bond,so it is $sp^2$ hybrid

Vedclass · Accepted Answer

$H_2C = CH - C \equiv N$

Vedclass · Answer

(A) In the molecule $H_2C = CH - C \equiv N$:$1$. The first carbon atom $(CH_2)$ is bonded to two hydrogens and one double bond,so it is $sp^2$ hybridized.$2$. The second carbon atom $(CH)$ is bonded to one hydrogen,one double bond,and one single bond,so it is $sp^2$ hybridized.$3$. The third carbon atom $(C)$ is bonded to one single bond and one triple bond,so it is $sp$ hybridized.$4$. The nitrogen atom $(N)$ is bonded to one triple bond and has one lone pair,so it is $sp$ hybridized.Thus,the hybridization sequence is $sp^2 - sp^2 - sp - sp$.

Which of the following compounds shows the hybridization mode $sp^2 - sp^2 - sp - sp$ from left to right?

Similar Questions

What is the bond angle $\angle F-B-F$ in $BF_3$ (in $^{\circ}$)?

Differentiate between atomic orbitals and hybrid orbitals.

Which of the following shows a linear structure?

The valency of carbon is $4$. On what principle can it be explained in a better way?

Which pair of molecules has different hybridisation but the same shape?

Vedclass Test Series

Exam Paper Generator

Online Exam Module