Which of the following molecules does not exi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Molecular Orbital Theory,the bond order is calculated as: $Bond \ Order = \frac{1}{2} (N_b - N_a)$,where $N_b$ is the number of elect

Vedclass · Accepted Answer

$He_2$

Vedclass · Answer

(C) According to Molecular Orbital Theory,the bond order is calculated as: $Bond \ Order = \frac{1}{2} (N_b - N_a)$,where $N_b$ is the number of electrons in bonding orbitals and $N_a$ is the number of electrons in antibonding orbitals.For $He_2$,the electronic configuration is $\sigma 1s^2, \sigma^* 1s^2$.Bond order = $\frac{1}{2} (2 - 2) = 0$.Since the bond order is $0$,the molecule $He_2$ does not exist.

Which of the following molecules does not exist on the basis of Molecular Orbital Theory?

Similar Questions

The ion that is isoelectronic with $CO$ is

Is the neon molecule $Ne_2$ possible? Why?

Explain the linear combination of atomic orbitals $(LCAO)$ with a suitable example.

What is the effect of the following processes on the bond order in $N_{2}$ and $O_{2}$?
$(A)$ $N_{2} \to N_{2}^{+} + e^{-}$
$(B)$ $O_{2} \to O_{2}^{+} + e^{-}$

Total number of electrons present in $(\pi^*)$ molecular orbitals of $O_2$,$O_2^{+}$,and $O_2^{-}$ is ............

Vedclass Test Series

Exam Paper Generator

Online Exam Module