Which of the following does not show geometri | vedclass

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(D) Geometrical isomerism requires restricted rotation and different groups on each carbon atom of the double bond.$A$. $CH_3-CH=CH-CH_3$ (but$-2-$ene

Vedclass · Accepted Answer

ethylidenecyclohexane

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(D) Geometrical isomerism requires restricted rotation and different groups on each carbon atom of the double bond.$A$. $CH_3-CH=CH-CH_3$ (but$-2-$ene) shows geometrical isomerism (cis and trans isomers).$B$. $CHCl=C=CHCl$ is an allene. For an allene $abC=C=Ccd$ to show geometrical isomerism,$a 
eq b$ and $c 
eq d$. Here,$a=H, b=Cl$ and $c=H, d=Cl$. Since $a 
eq b$ and $c 
eq d$,it shows geometrical isomerism.$C$. $1,2-$dimethylcyclohexane shows geometrical isomerism due to the restricted rotation of the cyclohexane ring (cis and trans isomers).$D$. Ethylidenecyclohexane has the structure where the exocyclic double bond is connected to a cyclohexane ring. The carbon atom of the double bond outside the ring is bonded to two identical hydrogen atoms (if it were ethylidene,it would be $=CH-CH_3$,but the image shows $=CH-D$ where $D$ is deuterium). Wait,looking at the structure in option $D$,it is a cyclohexane ring with an exocyclic double bond to a $CH-D$ group. The carbon of the double bond attached to the ring has two identical groups (the ring carbons are symmetric),so it does not show geometrical isomerism.

Which of the following does not show geometrical isomerism?

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Which of the following will have geometrical isomers?

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