Which of the following electrolytes is most e | vedclass

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(D) According to the $Hardy-Schulze$ rule,the coagulating power of an electrolyte depends on the valency of the active ion (the ion carrying a charge

Vedclass · Accepted Answer

$MgCl_2$

Vedclass · Answer

(D) According to the $Hardy-Schulze$ rule,the coagulating power of an electrolyte depends on the valency of the active ion (the ion carrying a charge opposite to that of the colloidal particles).Gold solution is a negatively charged sol.Therefore,the coagulating power depends on the valency of the cation.However,in this specific case,the complex anion $[Fe(CN)_6]^{4-}$ has a high negative charge,but the question refers to the coagulation of a gold sol (which is negative). The effective coagulating ion must be a cation.Wait,gold sol is typically negative,so it requires a cation for coagulation. Among the given options,$MgCl_2$ provides $Mg^{2+}$,while others provide $Na^+$ or $K^+$.Actually,$K_4[Fe(CN)_6]$ is often cited in textbooks for specific interactions,but based on the $Hardy-Schulze$ rule for a negative sol,$MgCl_2$ $(Mg^{2+})$ is more effective than $Na^+$ or $K^+$.Given the standard context of this question,$K_4[Fe(CN)_6]$ is often the intended answer due to the high charge density of the complex ion,but strictly speaking,for a negative sol,$MgCl_2$ is the correct choice. Assuming the question implies the most effective coagulant provided,$MgCl_2$ is the answer.

Which of the following electrolytes is most effective in the coagulation of gold solution?

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