Which of the following electronic configurations will have nearly zero electronegativity?
- A$1s^2 \ 2s^2 \ 2p^5$
- B$1s^2 \ 2s^2 \ 2p^3$
- C$1s^2$
- D$1s^2 \ 2s^2$
Explore More
Similar Questions
The values of electronegativity of atoms $A$ and $B$ are $1.20$ and $4.0$ respectively. The percentage of ionic character of $A-B$ bond is ............. $\%$
Difficult
View SolutionWhich of the following is the correct order of electronegativity?
Medium
View SolutionThe increasing order of electronegativity is:
Easy
View SolutionAmong the following,the pairs of elements having approximately the same electronegativity values are:
$I$. $H$ and $P$
$II$. $Be$ and $Al$
$III$. $N$ and $Cl$
$IV$. $C$ and $P$
$I$. $H$ and $P$
$II$. $Be$ and $Al$
$III$. $N$ and $Cl$
$IV$. $C$ and $P$
Electronegativity is a measure of the capacity of an atom to
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo