Which of the following elements in their resp | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.$1$. For $M

Vedclass · Accepted Answer

$Mn^{2+}$

Vedclass · Answer

(A) The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.$1$. For $Mn^{2+}$ $(Z=25)$: Electronic configuration is $[Ar] 3d^5$. Number of unpaired electrons $(n)$ = $5$. $\mu = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \ BM$.$2$. For $Ti^{3+}$ $(Z=22)$: Electronic configuration is $[Ar] 3d^1$. Number of unpaired electrons $(n)$ = $1$. $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ BM$.$3$. For $Cu^{2+}$ $(Z=29)$: Electronic configuration is $[Ar] 3d^9$. Number of unpaired electrons $(n)$ = $1$. $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ BM$.$4$. For $Ni^{2+}$ $(Z=28)$: Electronic configuration is $[Ar] 3d^8$. Number of unpaired electrons $(n)$ = $2$. $\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83 \ BM$.Comparing the values,$Mn^{2+}$ has the highest number of unpaired electrons and thus the highest magnetic moment.

Which of the following elements in their respective oxidation states develops the highest spin-only magnetic moment?

Similar Questions

How many unpaired electrons are present in cobalt $[Co]$ metal?

The outer electronic configuration of $Gd \ (At. \ No. \ 64)$ is

Which of the following metal ions has a calculated magnetic moment value of $\sqrt{24} \ BM$?

Which of the following pairs of elements does $NOT$ include transition elements?

Which element from the following does $NOT$ exhibit a magnetic moment in the $+2$ oxidation state?

Vedclass Test Series

Exam Paper Generator

Online Exam Module