Which of the following elements is $NOT$ radioactive?

  • A
    $At$
  • B
    $Po$
  • C
    $Rn$
  • D
    $Ar$

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Why does the following reaction occur?
$XeO_{6(aq)}^{4-} + 2F_{(aq)}^{-} + 6H_{(aq)}^{+} \to XeO_{3(g)} + F_{2(g)} + 3H_2O_{(l)}$
What conclusion about the compound $Na_4XeO_6$ (of which $XeO_6^{4-}$ is a part) can be drawn from the reaction?

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