Which of the following expressions is correct | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a $CsCl$ crystal structure,the $Cs^{+}$ ion is located at the body center,and $Cl^{-}$ ions are located at the corners of the cube.The body dia

Vedclass · Accepted Answer

$r_{Cs^{+}} + r_{Cl^{-}} = \frac{\sqrt{3}}{2} a$

Vedclass · Answer

(C) In a $CsCl$ crystal structure,the $Cs^{+}$ ion is located at the body center,and $Cl^{-}$ ions are located at the corners of the cube.The body diagonal of the cube is given by $\sqrt{3} a$.Since the $Cs^{+}$ ion at the center touches the $Cl^{-}$ ions at the corners along the body diagonal,the length of the body diagonal is equal to $2(r_{Cs^{+}} + r_{Cl^{-}})$.Therefore,$2(r_{Cs^{+}} + r_{Cl^{-}}) = \sqrt{3} a$.This simplifies to $r_{Cs^{+}} + r_{Cl^{-}} = \frac{\sqrt{3}}{2} a$.

Which of the following expressions is correct in the case of a $CsCl$ unit cell (edge length '$a$')?

Similar Questions

In a solid $AB$,$A$ atoms are in $ccp$ arrangement and $B$ atoms occupy all the octahedral sites. If two atoms from the opposite faces are removed,then the resultant stoichiometry of the compound is $A_{x} B_{y}$. The value of $x$ is ..... [nearest integer]

In an ${A^{+}}{B^{-}}$ ionic compound, the radii of ${A^{+}}$ and ${B^{-}}$ ions are $180 \ pm$ and $187 \ pm$ respectively. The crystal structure of this compound will be:

An $AB_2$ type structure is found in

The radius of the largest sphere which fits properly at the centre of the edge of a body-centered cubic $(BCC)$ unit cell is (Edge length is represented by $a$) (in $a$)

What is the coordination number of a sphere in a simple cubic lattice?

Vedclass Test Series

Exam Paper Generator

Online Exam Module