Which of the following functions have the max | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let us analyze each function:$1$. For $f(x) = \sin^2 x - \cos^2 x = -\cos 2x$,the range is $[-1, 1]$. The maximum value is $1$.$2$. For $f(x) = \f

Vedclass · Accepted Answer

All of the above

Vedclass · Answer

(D) Let us analyze each function:$1$. For $f(x) = \sin^2 x - \cos^2 x = -\cos 2x$,the range is $[-1, 1]$. The maximum value is $1$.$2$. For $f(x) = \frac{\sin 2x - \cos 2x}{\sqrt{2}}$,we can write this as $\sin(2x - \frac{\pi}{4})$. The range is $[-1, 1]$. The maximum value is $1$.$3$. For $f(x) = -\frac{\sin 2x - \cos 2x}{\sqrt{2}}$,we can write this as $-\sin(2x - \frac{\pi}{4}) = \sin(\frac{\pi}{4} - 2x)$. The range is $[-1, 1]$. The maximum value is $1$.Since all functions have a maximum value of $1$,the correct option is $D$.

Which of the following functions have the maximum value unity?

Similar Questions

If $A+B+C=\pi$,then $\sin A-\sin B+\sin C=$

The maximum value of $\cos \alpha_1 \cdot \cos \alpha_2 \cdots \cos \alpha_n$ under the restrictions $0 \le \alpha_1, \alpha_2, \dots, \alpha_n \le \frac{\pi}{2}$ and $\cot \alpha_1 \cdot \cot \alpha_2 \cdots \cot \alpha_n = 1$ is

$2^{\sin \theta} + 2^{\cos \theta}$ is greater than

If $A + B = \pi / 2$,then the maximum value of $\cos A \cos B$ is:

Let $x, y$ be positive real numbers and $m, n$ be positive integers. The maximum value of the expression $\frac{x^m y^n}{(1 + x^{2m})(1 + y^{2n})}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module