Which of the following gases has the highest | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The root mean square $(RMS)$ velocity of a gas is given by the formula $v_{	ext{rms}} = \sqrt{\frac{3RT}{M}}$.Since $R$ and $T$ are constant for

Vedclass · Accepted Answer

$CH_{4}$

Vedclass · Answer

(A) The root mean square $(RMS)$ velocity of a gas is given by the formula $v_{	ext{rms}} = \sqrt{\frac{3RT}{M}}$.Since $R$ and $T$ are constant for all gases at a given temperature,the $RMS$ velocity is inversely proportional to the square root of the molar mass,i.e.,$v_{	ext{rms}} \propto \frac{1}{\sqrt{M}}$.Comparing the molar masses $(M)$:$CH_{4} = 16 \ g/mol$$CO = 28 \ g/mol$$Cl_{2} = 71 \ g/mol$$CO_{2} = 44 \ g/mol$Since $CH_{4}$ has the lowest molar mass,it will have the highest $RMS$ velocity.

Which of the following gases has the highest value of $RMS$ velocity at $298 \ K$?

Similar Questions

At what temperature $(^o C)$ will the $rms$ speed of $CO_2$ be equal to the $rms$ speed of $CO$ at $STP$?

The gas that has the slowest rate of diffusion among $O_2$,$H_2$,$CO_2$ and $CH_4$ is

In which of the following pairs do the gaseous species diffuse with the same rate of diffusion under similar conditions of temperature and pressure?

Case $-1:$ An ideal gas of molecular weight $M$ at temperature $T$.
Case $-2:$ Another ideal gas of molecular weight $2M$ at temperature $T/2$.
Identify the correct statement in the context of the above two cases.

Explain the relationship between different types of molecular speeds.

Vedclass Test Series

Exam Paper Generator

Online Exam Module