Which of the following has been arranged in o | vedclass

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(D) Bond dissociation energy is inversely proportional to bond length: $BDE \propto \frac{1}{	ext{Bond length}}$.As we move from left to right across

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$Cl-O > S-O > P-O$

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(D) Bond dissociation energy is inversely proportional to bond length: $BDE \propto \frac{1}{	ext{Bond length}}$.As we move from left to right across a period,the atomic size decreases,which leads to a decrease in bond length.The order of atomic size is $P > S > Cl$,therefore the order of bond length is $P-O > S-O > Cl-O$.Since bond dissociation energy is inversely proportional to bond length,the order of $BDE$ is $Cl-O > S-O > P-O$.

Column $I$ (Molecules)	Column $II$ (Number of lone pairs on central atom)
$A. \ NH_3$	$1. \ \text{Two}$
$B. \ H_2O$	$2. \ \text{Three}$
$C. \ XeF_2$	$3. \ \text{Zero}$
$D. \ CH_4$	$4. \ \text{Four}$
	$5. \ \text{One}$

Which of the following has been arranged in order of decreasing bond dissociation energy:

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