Which of the following has the minimum value | vedclass

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(D) According to the $Hardy-Schulze$ rule,the flocculating power of an ion is directly proportional to the magnitude of the charge on the ion.Greater

Vedclass · Accepted Answer

$Na^{+}$

Vedclass · Answer

(D) According to the $Hardy-Schulze$ rule,the flocculating power of an ion is directly proportional to the magnitude of the charge on the ion.Greater the valency of the flocculating ion added,the greater is its power to cause precipitation.Comparing the charges: $Pb^{4+} > Pb^{2+} = Sr^{2+} > Na^{+}$.Therefore,the ion with the minimum charge has the minimum flocculating power.Among the given options,$Na^{+}$ has the minimum charge $(+1)$,so it has the minimum flocculating power.

Which of the following has the minimum value of flocculating power?

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