Which of the following orbitals has the least | vedclass

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(C) According to the $(n+l)$ rule,the energy of an orbital is determined by the sum of the principal quantum number $(n)$ and the azimuthal quantum nu

Vedclass · Accepted Answer

$2s$

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(C) According to the $(n+l)$ rule,the energy of an orbital is determined by the sum of the principal quantum number $(n)$ and the azimuthal quantum number $(l)$.For $2p$: $n=2, l=1$,so $(n+l) = 2+1 = 3$.For $3p$: $n=3, l=1$,so $(n+l) = 3+1 = 4$.For $2s$: $n=2, l=0$,so $(n+l) = 2+0 = 2$.For $4d$: $n=4, l=2$,so $(n+l) = 4+2 = 6$.Since the $2s$ orbital has the lowest $(n+l)$ value,it has the least energy.

Which of the following orbitals has the least energy?

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