Which of the following hydrocarbons reacts ea | vedclass

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(B) The reaction of $MeMgBr$ (a Grignard reagent) with hydrocarbons occurs if the hydrocarbon has an acidic hydrogen atom. $MeMgBr$ acts as a base and

Vedclass · Accepted Answer

Cyclopentadiene

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(B) The reaction of $MeMgBr$ (a Grignard reagent) with hydrocarbons occurs if the hydrocarbon has an acidic hydrogen atom. $MeMgBr$ acts as a base and abstracts the most acidic proton to form methane $(CH_4)$.Among the given options, $1,3$-cyclopentadiene contains a methylene group $(-CH_2-)$ between two double bonds. The hydrogen atoms on this carbon are significantly more acidic than those in other hydrocarbons because the resulting cyclopentadienyl anion is aromatic ($6\pi$ electrons, $H$ückel's rule), which provides high stability.Therefore, $1,3$-cyclopentadiene reacts readily with $MeMgBr$ to form methane and the cyclopentadienyl Grignard reagent.

Which of the following hydrocarbons reacts easily with $MeMgBr$ to give methane?

Similar Questions

Which one of the following has the minimum boiling point?

$CH_3-C(ONa)=CH_2$ $\xrightarrow{HC\equiv CH}$ $\xrightarrow{H^{+}}$ $\xrightarrow[Pd-BaSO_4]{H_2}$ $\xrightarrow[\Delta]{Al_2O_3}$
End product of the reaction is

Compound $(X)$ will be:
Compound $(X) \xrightarrow[Pt]{5H_2} \text{Saturated compound}$
Compound $(X) \xrightarrow{AgNO_3} \text{Precipitate}$
Compound $(X) \xrightarrow[Me_2S]{O_3} OHC-CH_2-CH_2-CO-CHO + HOOC-CHO + HCOOH + OHC-CHO$

The following reaction takes place in high yields. Use your knowledge of alkene chemistry to predict the product.

Which of the following compounds was the starting material for the oxidation shown below?

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