Which of the following ions can reduce dilute | vedclass

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Question

(A) For an ion to reduce dilute acid to hydrogen gas $(H_2)$,the standard electrode potential $(E^0)$ of the metal ion must be more negative than the

Vedclass · Accepted Answer

$Ti^{2+}, Cr^{2+}$

Vedclass · Answer

(A) For an ion to reduce dilute acid to hydrogen gas $(H_2)$,the standard electrode potential $(E^0)$ of the metal ion must be more negative than the standard reduction potential of hydrogen $(E^0_{H^+/H_2} = 0.00 \ V)$.This means the metal must be a strong enough reducing agent to donate electrons to $H^+$ ions.Among the given options,$Ti^{2+}$ $(E^0 = -0.37 \ V)$ and $Cr^{2+}$ $(E^0 = -0.41 \ V)$ have negative standard reduction potentials,making them capable of reducing $H^+$ to $H_2$ gas.$Mn^{3+}$ and $Co^{3+}$ have positive reduction potentials and act as oxidizing agents,not reducing agents.

Which of the following ions can reduce dilute acid to give hydrogen gas?

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Which of the following metal hydroxide is not soluble in excess of $NH_3$ solution?

The set of correct statements is:
$(i)$ Manganese exhibits $+7$ oxidation state in its oxide.
$(ii)$ Ruthenium and Osmium exhibit $+8$ oxidation state in their oxides.
$(iii)$ $Sc$ shows $+4$ oxidation state which is oxidizing in nature.
$(iv)$ $Cr$ shows oxidizing nature in $+6$ oxidation state.

How many statements are incorrect?
$(a)$ $Mn^{+3}$ and $Co^{+3}$ are strong oxidising agents.
$(b)$ $Ti^{+2}$,$V^{+2}$ and $Cr^{+2}$ are strong reducing agents.
$(c)$ $CrO_3$ is acidic in nature.
$(d)$ $E^{\circ}_{M^{+3}/M^{+2}} = -ve$ for $Fe$.

Identify the correct statement.

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