Which of the following ions has the highest m | vedclass

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(C) The magnetic moment $\mu$ is calculated using the formula $\mu = \sqrt{n(n + 2)} 	ext{ BM}$,where $n$ is the number of unpaired electrons.$Ti^{3+

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$Mn^{2+}$

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(C) The magnetic moment $\mu$ is calculated using the formula $\mu = \sqrt{n(n + 2)} 	ext{ BM}$,where $n$ is the number of unpaired electrons.$Ti^{3+}$ $(Z=22)$: $3d^1$,$n = 1$.$Sc^{3+}$ $(Z=21)$: $3d^0$,$n = 0$.$Mn^{2+}$ $(Z=25)$: $3d^5$,$n = 5$.$Zn^{2+}$ $(Z=30)$: $3d^{10}$,$n = 0$.Since $Mn^{2+}$ has the highest number of unpaired electrons $(n = 5)$,it exhibits the highest magnetic moment.

Which of the following ions has the highest magnetic moment?

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