Which of the following ions has the least mag | vedclass

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Question

(A) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n + 2)} 	ext{ BM}$,where $n$ is the number of unpaired electrons.
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Vedclass · Accepted Answer

$Cu^{2+}$

Vedclass · Answer

(A) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n + 2)} 	ext{ BM}$,where $n$ is the number of unpaired electrons.
Since $\mu \propto \sqrt{n}$,the ion with the fewest unpaired electrons will have the least magnetic moment.

	
		
			Ion
			Electronic configuration / Unpaired electrons $(n)$
		
		
			$Cu^{2+}$
			$d^9$ / $1$
		
		
			$Ni^{2+}$
			$d^8$ / $2$
		
		
			$Co^{2+}$
			$d^7$ / $3$
		
		
			$Fe^{2+}$
			$d^6$ / $4$
		
	


$Cu^{2+}$ has only $1$ unpaired electron,therefore it has the least magnetic moment.

Which of the following ions has the least magnetic moment?

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