Which of the following ions will have the min | vedclass

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(D) The reaction between $FeCl_3$ and excess $NaOH$ produces a negatively charged ferric hydroxide sol: $FeCl_3 + 3NaOH 	o Fe(OH)_3(s) + 3NaCl$. Due

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$Al^{3+}$

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(D) The reaction between $FeCl_3$ and excess $NaOH$ produces a negatively charged ferric hydroxide sol: $FeCl_3 + 3NaOH 	o Fe(OH)_3(s) + 3NaCl$. Due to the adsorption of $OH^-$ ions from the excess $NaOH$,the sol is negatively charged: $[Fe(OH)_3]OH^-$. According to the Hardy-Schulze rule,the coagulating power of an ion is directly proportional to its valency. For a negatively charged sol,the coagulating power increases with the valency of the cation. The valencies of the given cations are: $Ba^{2+}$ $(+2)$ and $Al^{3+}$ $(+3)$. Since $Al^{3+}$ has the highest valency among the cations,it has the maximum coagulating power and,therefore,the minimum coagulating value.

Which of the following ions will have the minimum coagulating value for the sol obtained by adding $FeCl_3$ solution to a slight excess of $NaOH$?

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