Which of the following is an inert element?

The type of hybridisation and number of lone pair$(s)$ of electrons of $Xe$ in $XeOF_4$ respectively are

$Xe_{(g)} + 2 F_{2(g)} \xrightarrow[7 \text{ bar }]{873 \text{ K}} XeF_{4(s)}$
The ratio of $Xe : F_2$ required in the above reaction is

Assertion $(A)$: The boiling points of noble gases increase from $He$ to $Xe$.
Reason $(R)$: The interatomic van der Waals' attractive forces increase from $He$ to $Xe$.
The correct answer is:

Which inert gas has the highest boiling point?

The oxidation state of $Xe$ in $XeO_3$ and the bond angle in it respectively are: