Which of the following is arranged in decreas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given ions are $O^{2-}$,$Mg^{2+}$,and $Al^{3+}$.All these ions are isoelectronic,meaning they all have $10$ electrons ($O^{2-}: 8+2=10$,$Mg^{2

Vedclass · Accepted Answer

$O^{2-} > Mg^{2+} > Al^{3+}$

Vedclass · Answer

(B) The given ions are $O^{2-}$,$Mg^{2+}$,and $Al^{3+}$.All these ions are isoelectronic,meaning they all have $10$ electrons ($O^{2-}: 8+2=10$,$Mg^{2+}: 12-2=10$,$Al^{3+}: 13-3=10$).For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.The atomic numbers are $O=8$,$Mg=12$,and $Al=13$.Therefore,the decreasing order of size is $O^{2-} > Mg^{2+} > Al^{3+}$.

Which of the following is arranged in decreasing order of size?

Similar Questions

Which of the following atoms or ions has the smallest size?

Which of the following arrangements is correct regarding the three types of radii for an atom?

The ions $O^{2-}, F^{-}, Na^{+}, Mg^{2+}$ and $Al^{3+}$ are isoelectronic. Their ionic radii show

The single bond covalent radius $(SBCR)$ of $P$ is $0.11 \ nm$. The single bond covalent radius of $Cl$ is:

In the main group elements $(i)$ as we proceed down the same group in the periodic table and $(ii)$ as we proceed from left to right in the same period,the atomic radius

Vedclass Test Series

Exam Paper Generator

Online Exam Module