Which of the following statements is correct regarding the Arrhenius equation and reaction kinetics?

  • A
    Larger the activation energy,higher will be the value of temperature coefficient of reaction.
  • B
    With an increase in temperature,in the high-temperature range,the rate constant increases more as compared to the low-temperature range.
  • C
    The graph of $\ln k$ vs $\frac{1}{T}$ is a straight line with a slope of $-\frac{E_a}{R}$.
  • D
    Chemical reactions with low activation energy always occur at a faster rate compared to reactions with higher activation energy.

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Assertion : If the activation energy of a reaction is zero,temperature will have no effect on the rate constant.
Reason : Lower the activation energy,faster is the reaction.

At $300 \ K$,the activation energy and rate constant for the given reaction are $10 \ kJ \ mol^{-1}$ and $2.4 \times 10^{-5} \ s^{-1}$ respectively. At what temperature (in $K$) will the value of $t_{1/2}$ be $2 \ hr$?
$2N_2O_5 \to 4NO_2 + O_2$

In which of the following cases is the percentage increase in rate constant maximum?
$Case$$E_a \ (kcal/mol)$$Temp. \ Change \ (K)$
$I$$40$$200 - 210$
$II$$80$$200 - 210$
$III$$40$$300 - 310$
$IV$$80$$300 - 310$

If the rate constants of a reaction at $500 \ K$ and $700 \ K$ are $0.002 \ s^{-1}$ and $0.06 \ s^{-1}$,respectively,the value of activation energy is $(R=8.314 \ J \ mol^{-1} \ K^{-1}, \log 3=0.477)$.

The rate constants for the decomposition of acetaldehyde have been measured over the temperature range $700-1000 \ K$. The data has been analysed by plotting a $\ln \ k \ vs \ \frac{10^{3}}{T}$ graph,which gives a slope of $-18.5$. The value of activation energy for the reaction is $...... \ kJ \ mol^{-1}$. (Nearest integer) (Given: $R = 8.31 \ J \ K^{-1} \ mol^{-1}$)

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