Which of the following is Mendius reduction?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The correct answer is $D$. Mendius reduction involves the reduction of nitriles $(R-CN)$ to primary amines $(R-CH_2NH_2)$ using reducing agents li

Vedclass · Accepted Answer

$R-CN \xrightarrow[	ext{or } LiAlH_4]{Na / CH_3OH} R-CH_2NH_2$

Vedclass · Answer

(D) The correct answer is $D$. Mendius reduction involves the reduction of nitriles $(R-CN)$ to primary amines $(R-CH_2NH_2)$ using reducing agents like sodium in ethanol or methanol ($Na / C_2H_5OH$ or $Na / CH_3OH$) or lithium aluminum hydride $(LiAlH_4)$. Explanation of other options: - $A$: This is Hofmann bromamide degradation,where an amide $(R-CONH_2)$ reacts with bromine and alkali to form a primary amine. - $B$: This is the $N$-alkylation of amines,where an amine reacts with excess alkyl halide to form a quaternary ammonium salt. - $C$: This is Hofmann elimination,where a quaternary ammonium hydroxide undergoes thermal decomposition to form an alkene and a tertiary amine.

Similar Questions

Explain the method of preparation for amine compounds by the reduction of nitro compounds.

The major product '$P$' for the following sequence of reactions is:

Identify the major organic product formed from the following reaction sequence:
$CH_3-CH(CH_3)-CO-CH_3 \xrightarrow[(ii) LiAlH_4, (iii) H_2O]{(i) CH_3NH_2} \text{?}$

In which case is an alkylamine not formed?

Suggest a route by which the following conversion can be accomplished: Cyclohexanecarboxamide to $N$-methylcyclohexanamine.

Vedclass Test Series

Exam Paper Generator

Online Exam Module