Which of the following is paramagnetic?

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(A) Paramagnetism is due to the presence of unpaired electrons.In $O_2[AsF_6]$,the $O_2^+$ ion has a bond order of $2.5$ and contains one unpaired ele

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$O_2[AsF_6]$

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(A) Paramagnetism is due to the presence of unpaired electrons.In $O_2[AsF_6]$,the $O_2^+$ ion has a bond order of $2.5$ and contains one unpaired electron in its molecular orbitals,making it paramagnetic.$Al_2O_3$ is an ionic solid where $Al^{3+}$ ($[Ne]$ configuration) and $O^{2-}$ ($[Ne]$ configuration) have no unpaired electrons,making it diamagnetic.For $C_2$,the molecular orbital configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2, \pi 2p_y^2$. All electrons are paired,so it is diamagnetic.For $Be_2$,the configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2$. All electrons are paired,so it is diamagnetic.

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