Which of the following is paramagnetic?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) . Elements or ions containing unpaired electrons are paramagnetic.$_{28}Ni = [Ar] \; 3d^8 4s^2$; $Ni^{2+} = [Ar] \; 3d^8 4s^0$.In $Ni^{2+}$,the $3

Vedclass · Accepted Answer

$Ni^{2+}$

Vedclass · Answer

(A) . Elements or ions containing unpaired electrons are paramagnetic.$_{28}Ni = [Ar] \; 3d^8 4s^2$; $Ni^{2+} = [Ar] \; 3d^8 4s^0$.In $Ni^{2+}$,the $3d$ subshell has $8$ electrons,which means there are $2$ unpaired electrons.$_{29}Cu^+ = [Ar] \; 3d^{10} 4s^0$ (diamagnetic).$_{30}Zn^{2+} = [Ar] \; 3d^{10} 4s^0$ (diamagnetic).$_{21}Sc^{3+} = [Ar] \; 3d^0 4s^0$ (diamagnetic).Since $Ni^{2+}$ has unpaired electrons,it is paramagnetic.

Similar Questions

Assertion : Cuprous ion $(Cu^+)$ has unpaired electrons while cupric ion $(Cu^{2+})$ does not.
Reason : Cuprous ion $(Cu^+)$ is colourless whereas cupric ion $(Cu^{2+})$ is blue in the aqueous solution.

Discuss the position of $d$-block elements in the periodic table.

What are alloys? Write about them.

The element with atomic number $23$ is placed in the periodic table in:

The magnetic moment of $2.84 \, B.M.$ is exhibited by which of the following ions? (Atomic numbers: $Ni = 28, Ti = 22, Cr = 24, Co = 27$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module