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(B) For the $2s$ orbital,the number of radial nodes is calculated using the formula: $	ext{Radial nodes} = n - l - 1$.For $2s$,$n = 2$ and $l = 0$,so

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(B) For the $2s$ orbital,the number of radial nodes is calculated using the formula: $	ext{Radial nodes} = n - l - 1$.For $2s$,$n = 2$ and $l = 0$,so $	ext{Radial nodes} = 2 - 0 - 1 = 1$.This means there is one point where the probability density $\psi^{2}(r)$ becomes zero.Also,the probability density $\psi^{2}(r)$ is always non-negative,meaning it cannot go below the $r$-axis.Among the given plots,option $B$ shows the probability density starting from a high value at the nucleus,touching the $r$-axis at one radial node,and then rising again before decaying,which correctly represents the $2s$ orbital.

Which of the following is the correct plot for the probability density $\psi^{2}(r)$ as a function of distance '$r$' of the electron from the nucleus for $2s$ orbital?

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