Which of the following is the least stable ca | vedclass

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(B) The stability of carbocations is determined by factors like resonance,hyperconjugation,and inductive effects.$1$. $CH_3-\stackrel{\oplus}{C}H_2$ (

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$CH_2=\stackrel{\oplus}{C}H$

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(B) The stability of carbocations is determined by factors like resonance,hyperconjugation,and inductive effects.$1$. $CH_3-\stackrel{\oplus}{C}H_2$ (Ethyl carbocation) is stabilized by hyperconjugation.$2$. $CH_2=\stackrel{\oplus}{C}H$ (Vinyl carbocation) has the positive charge on an $sp$-hybridized carbon atom. Since $sp$ carbons are more electronegative,they hold the positive charge very poorly,making it highly unstable.$3$. $CH_2=CH-CH_2^{\oplus}$ (Allyl carbocation) is stabilized by resonance.$4$. $C_6H_5-\stackrel{\oplus}{C}H_2$ (Benzyl carbocation) is stabilized by resonance with the benzene ring.Therefore,the vinyl carbocation is the least stable.

Which of the following is the least stable carbocation?

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Intermediates formed in the reactions $P$ and $Q$ are:
$P: CH_3-CH=CH_2 \xrightarrow{HCl}$
$Q: CH_3-CH=CH_2 \xrightarrow[\text{Peroxide}]{HCl}$

Arrange the following carbanions in the decreasing order of stability:
$I. \ p-Br-C_6H_4-CH_2^-$
$II. \ C_6H_5-CH_2^-$
$III. \ p-CH_3O-C_6H_4-CH_2^-$
$IV. \ p-CHO-C_6H_4-CH_2^-$
$V. \ p-CH_3-C_6H_4-CH_2^-$
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