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(D) Ferric hydroxide solution is a positively charged sol. According to the Hardy-Schulze rule,the greater the valence of the coagulating ion,the grea

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$K_3[Fe(CN)_6]$

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(D) Ferric hydroxide solution is a positively charged sol. According to the Hardy-Schulze rule,the greater the valence of the coagulating ion,the greater is its power to cause coagulation. $KCl \rightleftarrows K^{+} + Cl^{-}$ $KNO_3 \rightleftarrows K^{+} + NO_3^{-}$ $K_2SO_4 \rightleftarrows 2K^{+} + SO_4^{2-}$ $K_3[Fe(CN)_6] \rightleftarrows 3K^{+} + [Fe(CN)_6]^{3-}$ Since the ferric hydroxide sol is positively charged,it is coagulated by negative ions. The valency of the negative ion is highest in $[Fe(CN)_6]^{3-}$ (i.e.,$3$). Hence,$K_3[Fe(CN)_6]$ will be most effective in causing coagulation of ferric hydroxide solution.

Conc. of $Cl^{-}$ in $mol \cdot L^{-1}$	Result
$5 \times 10^{-5}$	Sol not precipitated
$6 \times 10^{-5}$	Sol not precipitated
$7 \times 10^{-5}$	Sol precipitated
$8 \times 10^{-5}$	Sol precipitated
$1 \times 10^{-4}$	Sol precipitated

Which of the following is the most effective in causing coagulation of ferric hydroxide solution?

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