Which of the following is the strongest base?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In aniline,$N$-methylaniline,and o-toluidine,the lone pair of electrons on the nitrogen atom is in conjugation with the benzene ring,which decreas

Vedclass · Accepted Answer

Benzylamine $(C_6H_5CH_2NH_2)$

Vedclass · Answer

(D) In aniline,$N$-methylaniline,and o-toluidine,the lone pair of electrons on the nitrogen atom is in conjugation with the benzene ring,which decreases its availability for protonation,making them weaker bases.In benzylamine $(C_6H_5CH_2NH_2)$,the lone pair on the nitrogen atom is not in conjugation with the benzene ring because of the presence of a $-CH_2-$ group between the benzene ring and the nitrogen atom.Therefore,the lone pair is more available for protonation,making benzylamine the strongest base among the given compounds.

Similar Questions

For the following diazonium ions,the order of reactivity towards diazo-coupling with phenol in the presence of dilute $NaOH$ is:
$(I)$ $p-Me_2N-C_6H_4-N_2^+$
$(II)$ $p-O_2N-C_6H_4-N_2^+$
$(III)$ $p-CH_3O-C_6H_4-N_2^+$
$(IV)$ $p-CH_3-C_6H_4-N_2^+$

Benzene diazonium chloride on reaction with ethanol forms

In the carbylamine reaction,hot alcoholic $KOH$ and ...... are required.

The reaction of ethylamine and acetic anhydride leads to the formation of:

How many amines with molecular formula $C_3H_9N$ can react with benzene sulphonyl chloride?

Vedclass Test Series

Exam Paper Generator

Online Exam Module