Which of the following is true for elastic potential energy density?
- AEnergy density $=$ $\frac{1}{2} \times \text{strain} \times \text{stress}$
- BEnergy density $=$ $(\text{strain})^2 \times \text{volume}$
- CEnergy density $=$ $\text{strain} \times \text{volume}$
- DEnergy density $=$ $\text{stress} \times \text{volume}$
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Similar Questions
If the work done in stretching a wire by $1 \ mm$ is $2 \ J$,the work necessary for stretching another wire of same material but with double radius of cross-section and half the length by $1 \ mm$ is $.... \ J$.
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View SolutionTwo wires of the same material (Young's modulus $Y$) and same length $L$ but radii $R$ and $2R$ respectively are joined end to end and a weight $W$ is suspended from the combination as shown in the figure. The elastic potential energy in the system is
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View SolutionWhat is the work done in stretching a uniform metal wire of length $2 \ m$ to $2.004 \ m$ with an area of cross-section $10^{-6} \ m^2$ (in $J$)? [Young's modulus of the wire = $2 \times 10^{11} \ N/m^2$]
$A$ $5 \, m$ long wire is fixed to the ceiling. $A$ weight of $10 \, kg$ is hung at the lower end and is $1 \, m$ above the floor. The wire is elongated by $1 \, mm$. The energy stored in the wire due to stretching is ......... $J$.
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View SolutionWhen a block of mass $M$ is suspended by a long wire of length $L$,the length of the wire becomes $(L+l)$. The elastic potential energy stored in the extended wire is:
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